42 lines
1.1 KiB
C
42 lines
1.1 KiB
C
|
#include <stdio.h>
|
||
|
|
#include <math.h>
|
||
|
|
|
||
|
|
main()
|
||
|
|
{
|
||
|
|
int i;
|
||
|
|
for (i = 0; i < 10; i++)
|
||
|
|
{
|
||
|
|
printf("------------------------------------------------------\n");
|
||
|
|
printf ( "remainder of 5.3 / 2 is %f\n", remainder (5.3,2) );
|
||
|
|
printf ( "remainder of 18.5 / 4.2 is %f\n", remainder (18.5,4.2) );
|
||
|
|
//remainder of 5.3 / 2 is -0.700000
|
||
|
|
//remainder of 18.5 / 4.2 is 1.700000
|
||
|
|
|
||
|
|
printf ( "fmod of 5.3 / 2 is %f\n", fmod (5.3,2) );
|
||
|
|
printf ( "fmod of 18.5 / 4.2 is %f\n", fmod (18.5,4.2) );
|
||
|
|
// fmod of 5.3 / 2 is 1.300000
|
||
|
|
// fmod of 18.5 / 4.2 is 1.700000
|
||
|
|
|
||
|
|
double param, fractpart, intpart, result;
|
||
|
|
int n;
|
||
|
|
|
||
|
|
param = 3.14159265;
|
||
|
|
fractpart = modf (param , &intpart);
|
||
|
|
printf ("%f = %f + %f \n", param, intpart, fractpart);
|
||
|
|
//3.141593 = 3.000000 + 0.141593
|
||
|
|
|
||
|
|
param = 0.95;
|
||
|
|
n = 4;
|
||
|
|
result = ldexp (param , n);
|
||
|
|
printf ("%f * 2^%d = %f\n", param, n, result);
|
||
|
|
//0.950000 * 2^4 = 15.200000
|
||
|
|
|
||
|
|
param = 8.0;
|
||
|
|
result = frexp (param , &n);
|
||
|
|
printf ("%f = %f * 2^%d\n", param, result, n);
|
||
|
|
//8.000000 = 0.500000 * 2^4
|
||
|
|
param = 50;
|
||
|
|
result = frexp (param , &n);
|
||
|
|
printf ("%f = %f * 2^%d\n", param, result, n);
|
||
|
|
}
|
||
|
|
}
|