kolibrios-fun/programs/network/ssh/mpint.inc
pathoswithin 97bb3982a6 small speedup
git-svn-id: svn://kolibrios.org@6423 a494cfbc-eb01-0410-851d-a64ba20cac60
2016-05-10 19:33:26 +00:00

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; mpint.inc - Multi precision integer procedures
;
; Copyright (C) 2015-2016 Jeffrey Amelynck
;
; This program is free software: you can redistribute it and/or modify
; it under the terms of the GNU General Public License as published by
; the Free Software Foundation, either version 3 of the License, or
; (at your option) any later version.
;
; This program is distributed in the hope that it will be useful,
; but WITHOUT ANY WARRANTY; without even the implied warranty of
; MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
; GNU General Public License for more details.
;
; You should have received a copy of the GNU General Public License
; along with this program. If not, see <http://www.gnu.org/licenses/>.
MPINT_MAX_LEN = MAX_BITS/8
; TODO: make procedures use real number length instead of hardcoded maximum length (MPINT_MAX_LEN)
mpint_to_little_endian:
; Load length dword
lodsd
; Convert to little endian
bswap eax
stosd
test eax, eax
jz .zero
; Copy data, convert to little endian meanwhile
push eax
add esi, eax
push esi
dec esi
mov ecx, eax
std
@@:
lodsb
mov byte[edi], al
inc edi
dec ecx
jnz @r
cld
pop esi eax
; Fill the rest of the buffer with zeros.
.zero:
mov ecx, MAX_BITS/8
sub ecx, eax
xor al, al
rep stosb
ret
mpint_to_big_endian:
; Load length dword
lodsd
test eax, eax
jz .zero
mov ecx, eax
add esi, ecx
dec esi
test byte[esi], 0x80 ; Is the highest bit set?
jz @f
inc eax
@@:
push eax
bswap eax
stosd
; Copy data, convert to big endian meanwhile
std
; Append zero byte if highest bit is 0
test byte[esi], 0x80
jz @f
mov byte[edi], 0
inc edi
@@:
lodsb
mov byte[edi], al
inc edi
dec ecx
jnz @r
cld
pop eax
ret
.zero:
stosd
ret
proc mpint_length uses edi eax ecx, mpint
mov edi, [mpint]
mov ecx, MPINT_MAX_LEN
push edi
lea edi, [edi + ecx + 4 - 1]
xor al, al
std
repe scasb
cld
je @f
inc ecx
@@:
pop edi
mov [edi], ecx
ret
endp
proc mpint_print uses ecx esi eax, src
DEBUGF 1, "0x"
mov esi, [src]
mov ecx, [esi]
test ecx, ecx
jz .zero
lea esi, [esi + ecx + 4 - 1]
pushf
std
.loop:
lodsb
DEBUGF 1, "%x", eax:2
dec ecx
jnz .loop
DEBUGF 1, "\n"
popf
ret
.zero:
DEBUGF 1, "00\n"
ret
endp
proc mpint_zero uses edi ecx eax, dst
mov edi, [dst]
xor eax, eax
mov ecx, MPINT_MAX_LEN/4+1
rep stosd
ret
endp
proc mpint_zero? uses edi ecx eax, dst
mov edi, [dst]
add edi, 4
mov ecx, MPINT_MAX_LEN/4
xor eax, eax
repe scasd
ret
endp
; return an index number giving the position of the highest order bit
proc mpint_hob uses edi ecx, dst
mov edi, [dst]
; start from the high order byte
add edi, MPINT_MAX_LEN+4-1
mov ecx, MPINT_MAX_LEN
xor eax, eax
; scan byte by byte for the first non-zero byte
std
repe scasb
cld
je .zero
; calculate how many bits this is, plus 7
lea eax, [ecx*8-1]
; load this high order byte into cl
mov cl, [edi+1]
; shift bits of this byte right, until the byte reaches zero, counting bits meanwhile
@@:
inc eax
shr cl, 1
jnz @r
.zero:
ret
endp
proc mpint_cmp uses esi edi ecx, dst, src
mov esi, [src]
mov edi, [dst]
; start from the high order byte
add esi, MPINT_MAX_LEN+4-4
add edi, MPINT_MAX_LEN+4-4
mov ecx, MPINT_MAX_LEN/4
std
repe cmpsd
cld
ret
endp
proc mpint_mov uses esi edi ecx, dst, src
mov esi, [src]
mov edi, [dst]
mov ecx, MPINT_MAX_LEN/4+1
rep movsd
ret
endp
proc mpint_mov0 uses esi edi ecx eax, dst, src
mov esi, [src]
mov edi, [dst]
mov ecx, [esi]
mov eax, ecx
neg eax
add esi, 4
add edi, 4
rep movsb
add eax, MPINT_MAX_LEN
jz @f
mov ecx, eax
xor eax, eax
rep stosb
@@:
ret
endp
proc mpint_shl1 uses edi ecx eax, dst
mov edi, [dst]
add edi, 4
mov ecx, MPINT_MAX_LEN/4-1
shl dword[edi], 1
lahf
@@:
add edi, 4
sahf
rcl dword[edi], 1
lahf
dec ecx
jnz @r
sahf
ret
endp
proc mpint_shr1 uses edi ecx eax, dst
mov edi, [dst]
add edi, MPINT_MAX_LEN+4-4
mov ecx, MPINT_MAX_LEN/4-1
shr dword[edi], 1
lahf
@@:
sub edi, 4
sahf
rcr dword[edi], 1
lahf
dec ecx
jnz @r
sahf
ret
endp
proc mpint_shl uses eax ebx ecx edx esi edi, dst, shift
mov ecx, [shift]
shr ecx, 3 ; 8 bits in one byte
cmp ecx, MPINT_MAX_LEN
jge .zero
mov esi, [dst]
add esi, MPINT_MAX_LEN+4-4
mov edi, esi
and ecx, not 11b
sub esi, ecx
mov edx, MPINT_MAX_LEN/4-1
shr ecx, 2 ; 4 bytes in one dword
push ecx
sub edx, ecx
mov ecx, [shift]
and ecx, 11111b
std
.loop:
lodsd
mov ebx, [esi]
shld eax, ebx, cl
stosd
dec edx
jnz .loop
lodsd
shl eax, cl
stosd
; fill the lsb bytes with zeros
pop ecx
test ecx, ecx
jz @f
xor eax, eax
rep stosd
@@:
cld
ret
.zero:
stdcall mpint_zero, [dst]
ret
endp
; Left shift and copy
proc mpint_shlmov uses eax ebx ecx edx esi edi, dst, src, shift
mov ecx, [shift]
shr ecx, 3 ; 8 bits in one byte
cmp ecx, MPINT_MAX_LEN
jge .zero
mov esi, [src]
add esi, MPINT_MAX_LEN+4-4
mov edi, [dst]
add edi, MPINT_MAX_LEN+4-4
and ecx, not 11b
sub esi, ecx
mov edx, MPINT_MAX_LEN/4-1
shr ecx, 2 ; 4 bytes in one dword
push ecx
sub edx, ecx
mov ecx, [shift]
and ecx, 11111b
std
.loop:
lodsd
mov ebx, [esi]
shld eax, ebx, cl
stosd
dec edx
jnz .loop
lodsd
shl eax, cl
stosd
; fill the lsb bytes with zeros
pop ecx
test ecx, ecx
jz @f
xor eax, eax
rep stosd
@@:
cld
ret
.zero:
stdcall mpint_zero, [dst]
ret
endp
proc mpint_add uses esi edi ecx eax, dst, src
mov esi, [src]
add esi, 4
mov edi, [dst]
add edi, 4
mov ecx, MPINT_MAX_LEN/4
xor ah, ah ; clear flags (Carry flag most importantly)
@@:
sahf
lodsd
adc [edi], eax
lahf
add edi, 4
dec ecx
jnz @r
sahf
ret
endp
proc mpint_sub uses eax esi edi ecx, dst, src
mov esi, [src]
add esi, 4
mov edi, [dst]
add edi, 4
mov ecx, MPINT_MAX_LEN/4
.loop:
lodsd
sub [edi], eax
jnc @f
dec dword [edi+4]
@@:
add edi, 4
dec ecx
jnz .loop
ret
endp
proc mpint_mul uses esi edi ecx ebx eax, dst, A, B
stdcall mpint_zero, [dst]
; first, find the byte in A containing the highest order bit
mov ecx, MPINT_MAX_LEN
mov edi, [A]
add edi, MPINT_MAX_LEN+4-1
std
xor al, al
repe scasb
cld
je .zero
inc ecx
mov al, [edi+1]
mov esi, edi
mov bl, 8
@@:
shl al, 1
jc .first_hit
dec bl
jnz @r
; Then, starting from this byte, iterate through the bits in A,
; starting from the highest order bit down to the lowest order bit.
.next_byte:
mov al, [edi]
dec edi
mov bl, 8
.next_bit:
stdcall mpint_shl1, [dst]
shl al, 1
jnc .zero_bit
.first_hit:
stdcall mpint_add, [dst], [B]
.zero_bit:
dec bl
jnz .next_bit
dec ecx
jnz .next_byte
.zero:
ret
endp
proc mpint_mod uses eax ecx, dst, mod
; if mod is zero, return
stdcall mpint_zero?, [mod]
jz .zero
stdcall mpint_cmp, [mod], [dst]
jb .done ; if dst < mod, dst = dst
je .zero ; if dst == mod, dst = 0
; left shift mod until the high order bits of mod and dst are aligned
stdcall mpint_hob, [dst]
mov ecx, eax
stdcall mpint_hob, [mod]
sub ecx, eax
stdcall mpint_shlmov, mpint_tmp, [mod], ecx
inc ecx
; For every bit in dst (starting from the high order bit):
.loop:
; determine if dst is bigger than mpint_tmp
stdcall mpint_cmp, [dst], mpint_tmp
ja @f
; if so, subtract mpint_tmp from dst
stdcall mpint_sub, [dst], mpint_tmp
@@:
dec ecx
jz .done
; shift mpint_tmp right by 1
stdcall mpint_shr1, mpint_tmp
jmp .loop
.zero:
stdcall mpint_zero, [dst]
.done:
ret
endp
proc mpint_modexp uses edi eax ebx ecx, dst, base, exp, mod
; If mod is zero, return
stdcall mpint_zero?, [mod]
jz .mod_zero
; Find the highest order byte in exponent
mov edi, [exp]
mov ecx, [edi]
lea edi, [edi + 4 + ecx - 1]
; Find the highest order bit in this byte
mov al, [edi]
test al, al
jz .invalid
mov bl, 9
@@:
dec bl
shl al, 1
jnc @r
; Initialise result to base, to take care of the highest order bit
stdcall mpint_mov0, [dst], [base]
dec bl
jz .next_byte
.bit_loop:
; For each bit, square result
stdcall mpint_mov, mpint_tmp, [dst]
stdcall mpint_mul, [dst], mpint_tmp, mpint_tmp
stdcall mpint_mod, [dst], [mod]
; If the bit is set, multiply result by the base
shl al, 1
jnc .next_bit
stdcall mpint_mov, mpint_tmp, [dst]
stdcall mpint_mul, [dst], [base], mpint_tmp
stdcall mpint_mod, [dst], [mod]
.next_bit:
dec bl
jnz .bit_loop
.next_byte:
dec ecx
jz .done
dec edi
mov al, [edi]
mov bl, 8
jmp .bit_loop
.done:
ret
.mod_zero:
DEBUGF 1, "modexp with modulo 0\n"
; if mod is zero, result = 0
stdcall mpint_zero, [dst]
ret
.exp_zero:
DEBUGF 1, "modexp with exponent 0\n"
; if exponent is zero, result = 1
stdcall mpint_zero, [dst]
mov eax, [dst]
mov byte[eax], 1
mov byte[eax+4], 1
ret
.invalid:
DEBUGF 1, "modexp: Invalid input!\n"
ret
endp