2009-12-29 00:19:20 +01:00
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; strlen function
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;
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; Copyright (c) 2003 Thomas Mathys
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; killer@vantage.ch
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;
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; This program is free software; you can redistribute it and/or modify
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; it under the terms of the GNU General Public License as published by
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; the Free Software Foundation; either version 2 of the License, or
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; (at your option) any later version.
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;
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; This program is distributed in the hope that it will be useful,
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; but WITHOUT ANY WARRANTY; without even the implied warranty of
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; MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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; GNU General Public License for more details.
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;
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; You should have received a copy of the GNU General Public License
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; along with this program; if not, write to the Free Software
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; Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
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;
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;%ifndef _STRLEN_INC
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;%define _STRLEN_INC
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;********************************************************************
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; returns the length of an asciiz string
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; input : esi = pointer to string
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; output : eax = string length
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; destroys : nothing
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;********************************************************************
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strlen:
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2010-05-27 16:46:37 +02:00
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push ecx edi
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2009-12-29 00:19:20 +01:00
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pushfd
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cld ; !
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mov ecx,-1
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mov edi,esi ; find terminating zero
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xor al,al
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repne scasb
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mov eax,edi ; calculate string length
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sub eax,esi
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dec eax
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popfd
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2010-05-27 16:46:37 +02:00
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pop edi ecx
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2009-12-29 00:19:20 +01:00
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ret
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; linlen function
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;
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; Copyright (c) 2009 Igor Afanasiev
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linlen:
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2010-05-27 16:46:37 +02:00
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push ecx edi
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2009-12-29 00:19:20 +01:00
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pushfd
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2013-02-14 22:09:13 +01:00
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cld
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2009-12-29 00:19:20 +01:00
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mov ecx,eax
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2013-02-14 22:09:13 +01:00
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inc ecx
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2009-12-29 00:19:20 +01:00
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mov edi,esi ; find terminating zero
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mov al,13
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repne scasb
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mov eax,edi ; calculate string length
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sub eax,esi
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dec eax
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popfd
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2010-05-27 16:46:37 +02:00
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pop edi ecx
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2009-12-29 00:19:20 +01:00
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ret
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2013-02-14 22:09:13 +01:00
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;description:
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; проверяет содержится ли строка str1 в строке str0
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; проверка делается только начиная с первых символов, указанных в str0 и str1
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; пример 1: если str0='aaabbbccc', str1='bbb' совпадения не будет
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; пример 2: если str0='aaabbbccc', str1='aaa' совпадение будет
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;output:
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; al = 0 если строка str1 содержится в str0
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; al != 0 если строка str1 не содержится в str0
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align 4
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proc str_instr uses edi esi, str0:dword, str1:dword
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;xor eax,eax
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mov edi,[str0]
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mov esi,[str1]
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cld
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@@:
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mov al,[esi]
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cmp al,0
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je .e1
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inc esi
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scasb ;сравниваем символы
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jz @b ;если совпали, то переходим к сравнению следующих
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;сюда попадаем если строки не совпали
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sub al,[edi-1]
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.e1: ;сюда попадаем если строка str1 (esi) закончилась
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ret
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endp
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2009-12-29 00:19:20 +01:00
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